The minimum value of $f(x) = 4x^3 - 48 x - CUETMOCK

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Home Questions 62D2FHEMFQ

Target Exam

CUET

Subject

-- Mathematics - Section B2

Chapter

Calculus

Question:

The minimum value of $f(x) = 4x^3 - 48 x + 105 $ in the interval [1, 3] is :

Options:

61

41

32

69

Correct Answer:

41

CUET Questions