The rate of change of the area of a circle with respect to its radius $r$, when $r = 3\,cm$, is: |
$6π\, cm^2/cm$ $4π\, cm^2/cm$ $2π\, cm^2/cm$ $3π\, cm^2/cm$ |
$6π\, cm^2/cm$ |
The correct answer is Option (1) → $6π\, cm^2/cm$ $\text{Area of circle }A=\pi r^2.$ $\frac{dA}{dr}=\frac{d}{dr}(\pi r^2).$ $\frac{dA}{dr}=2\pi r.$ $r=3.$ $\frac{dA}{dr}=2\pi(3).$ $\frac{dA}{dr}=6\pi.$ $\text{Rate of change of area}=6\pi\ \text{cm}.$ |