What is the value of (a + b + c) {( a- b)2 + ( b - c)2 + (c - a)2} ?
Answer & explanation
Correct answer: option 2
(a + b + c) {( a- b)2 + ( b - c)2 + (c - a)2} = ?
We know that ,
a3 + b3 + c3 - 3abc = \(\frac{1}{2}\)[(a + b + c) {( a- b)2 + ( b - c)2 + (c - a)2}]
2a3 + 2b3 +2c3 - 6abc = (a + b + c) {( a- b)2 + ( b - c)2 + (c - a)2}