Calculate the derivative $g(x)=\frac{3x+4}{2x-1}$ at $x=1$
Answer & explanation
Correct answer: option 3
$g'(x)=\frac{6x-3-6x-8}{(2x-1)^2}=\frac{-11}{(2x-1)^2}$. Hence $g'(1)=-11$
Calculate the derivative $g(x)=\frac{3x+4}{2x-1}$ at $x=1$
Correct answer: option 3
$g'(x)=\frac{6x-3-6x-8}{(2x-1)^2}=\frac{-11}{(2x-1)^2}$. Hence $g'(1)=-11$