Select the option that is related to the third letter-cluster in the same way as the second letter-cluster is related to the first letter-cluster.

KSZ : PHC :: TNK : ?

GMN

KSZ : PHC :: TNK : ?

The logic followed here is :

KSZ : PHC

AS

KSZ ⇒(opposite letter of K) (opposite letter of S) (Z+3) ⇒ PHC

Same as

TNK : ?

TNK ⇒(opposite letter of T) (opposite letter of N) (K+3) ⇒ GMN