If a - b = 7 and $a^2 + b^2 = 169$ where

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If a - b = 7 and $a^2 + b^2 = 169$ where a, b > 0, then the value of 3a + b is :

Options:

Correct Answer:

Explanation:

If a - b = 7 and $a^2 + b^2 = 169$ where a, b > 0,

then the value of 3a + b

Put the values of a = 12 and b = 5 ( These values will satisfy the given equation)

3a + b = 3(12) + 5 = 36 + 5

3a + b = 41