Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If A = $\frac{36÷18×5}{36÷(3×4)}$ and B = $\frac{5÷15×5+6×2-5}{15÷5×25-2×3+6}$,  then what is the value of ( A+ B) ?

Options:

$\frac{776}{225}$

$\frac{424}{225}$

$\frac{772}{225}$

$\frac{401}{225}$

Correct Answer:

$\frac{776}{225}$

Explanation:

If A = $\frac{36÷18×5}{36÷(3×4)}$ = \(\frac{10}{3}\)

B = $\frac{5÷15×5+6×2-5}{15÷5×25-2×3+6}$ =  $\frac{5 ÷ 3+7}{75}$ =  $\frac{26}{225}$

( A+ B) = \(\frac{10}{3}\) + $\frac{26}{225}$

( A+ B) = \(\frac{750 + 26}{225}\) = $\frac{776}{225}$