The instantaneous angular position of a point on a rotating wheel is given by the equation Ө (t) = 2t3 – 6t2. The torque on the wheel becomes zero at :
Answer & explanation
Correct answer: option 2
Torque : \(\tau = I \frac{d^2\theta(t)}{dt^2} = 0 \)
\(\tau = 0 \Rightarrow \frac{d^2 \theta}{dt^2} = 0\)
12 t - 12 = 0 ⇒ t = 1 s