Practicing Success
Practicing Success
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A is the point (3, 7, 5) and B is the point (–3, 2, 6). The projection of AB on the line which joins the points (7, 9, 4) and (4, 5, –8) is |
26 2 13 4 |
2 |
Distances of the line joining (7, 9, 4) and (4, 5, − 8) is <$\frac{3}{13}, \frac{4}{13}, \frac{12}{13}$> Therefore required projection is $\frac{26}{13}$ = 2 |
