The substrates required for the preparation of the following alcohol are
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) →
Correct answer: CH₃–CH₂–CH₂MgBr and acetophenone (C₆H₅–CO–CH₃)
Reason:
The given product is a tertiary alcohol with three groups attached to the carbon bearing –OH:
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Phenyl group (C₆H₅–)
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Methyl group (–CH₃)
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n-Propyl group (–CH₂CH₂CH₃)
In Grignard reactions, a tertiary alcohol is obtained by adding an alkyl Grignard reagent to a ketone.
Here:
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Acetophenone (C₆H₅–CO–CH₃) already provides the phenyl and methyl groups
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Addition of n-propyl magnesium bromide (CH₃–CH₂–CH₂MgBr) introduces the propyl group
After hydrolysis, the required alcohol is formed.