What is the increasing order of the oxidation state of the metal ion in following compounds?

(A). $ScBr_3$
(B). $V_2O_5$
(C). $CrF_6$
(D). $Tc_2O_7$

Choose the correct answer from the options given below:

(A), (B), (C), (D)

The correct answer is Option (1) → (A), (B), (C), (D)

We calculate the oxidation state ($x$) for the central metal atom in each compound, assuming standard oxidation states for the halogens and oxygen:

Increasing Order

Arranging the calculated oxidation states in increasing order:

$\mathbf{+3} < \mathbf{+5} < \mathbf{+6} < \mathbf{+7}$

Which corresponds to the order: $\mathbf{(A)} < \mathbf{(B)} < \mathbf{(C)} < \mathbf{(D)}$