What will be the number of genotypes and phenotypes obtained in F2 generation when male parent RRyy is crossed with female parent rrYY?

9 and 4 respectively

The correct answer is Option (3)- 9 and 4 respectively

In Mendel’s dihybrid cross,  cross is made between heterozygous round green seeds(RRyy) to another heterozygous wrinkled yellow seeds(rrYY). In the F₁ generation, all plants are heterozygous  Round yellow(RrYy).

Parents : RRyy X rrYY

F1: RrYy

Gametes : RY, Ry, rY, ry

 Genotypic ratio : 1:2:1:2:4:2:1:2:1

To find the genotypes and phenotypes in the F2 generation, we need to consider the possible combinations of alleles:

Genotypes: RRYY, RRYy, RRyy, RrYY, RrYy, Rryy, rrYY, rrYy, rryy (total 9)

Phenotypes: Round yellow, Round green, Wrinkled yellow, Wrinkled green (total 4)

So, the correct answer is (3)- 9 genotypes and 4 phenotypes.