The greatest number, which divides 641, 711 and 527 leaves the remainder 12, 8 and 10 respectively, is?
Answer & explanation
Correct answer: option 3
HCF of (641 - 12), (711 - 8), (1527 - 10)
HCF of 629, 703. 1517
↓ ↓ ↓
13×37 19×37 41×37
⇒ HCF = 37
Therefore, 37 is the greatest number, which divides 641, 711 and 527 leaves the remainder 12, 8 and 10 respectively.