The greatest number, which divides 641, 711 and 527 leaves the remainder 12, 8 and 10 respectively, is?

17 26 37 47

37

HCF of (641 - 12), (711 - 8), (1527 - 10) HCF of  629,       703.      1517               ↓            ↓            ↓          13×37    19×37     41×37 ⇒ HCF = 37 Therefore, 37 is the greatest number, which divides 641, 711 and 527 leaves the remainder 12, 8 and 10 respectively.