Practicing Success
Practicing Success
CUET Preparation Today
Given that at x=1, the function $x^4-62x^2+ax+90$ attains its maximum value on the interval [0, 2]. The value of 'a' is : |
130 120 -120 -128 |
120 |
The correct answer is Option (2) → 120 $y=x^4-62x^2+ax+90$ $\frac{dy}{dx}=4x^3-124x+a$ so $\left.\frac{dy}{dx}\right]_{x=1}=0$ so $4-124+a=0$ $a=120$ |
