The area of region bounded by the curve $y=cos x $ and x-axis between $x=0$ and $x= \pi $ is
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 2 sq.unit
By symmetry
Area of Region I = Area of Region II
Area = 2 × Area(Region I)
so $2×\int\limits_{0}^{π/2}\cos xdx=2[\sin x]_{0}^{π/2}$
= 2 sq. unit