The area of region bounded by the curve $y=cos x $ and x-axis between $x=0$ and $x= \pi $ is

1 sq.unit 2 sq.unit 3 sq.unit 4 sq.unit

2 sq.unit

The correct answer is Option (2) → 2 sq.unit By symmetry Area of Region I = Area of Region II Area = 2 × Area(Region I) so $2×\int\limits_{0}^{π/2}\cos xdx=2[\sin x]_{0}^{π/2}$ = 2 sq. unit