The 'stopping potential' in photoelectric emissions |
depends on both intensity and frequency of incident radiation. depends on frequency and not on intensity of incident radiation. depends on intensity and not on frequency of incident radiation. does not depend on intensity and frequency of incident radiation. |
depends on frequency and not on intensity of incident radiation. |
The correct answer is Option (2) → depends on frequency and not on intensity of incident radiation. Maximum kinetic energy of photoelectrons: $K_\text{max} = h \nu - \phi$ Stopping potential: $V_s = \frac{K_\text{max}}{e} = \frac{h \nu - \phi}{e}$ It depends on the frequency $\nu$, not on the intensity of incident light. Correct answer: depends on frequency and not on intensity of incident radiation |