Practicing Success
Calculate the maximum acceleration of a moving car so that a body lying on the door of the car remains stationary. The coefficient of static friction between the body and the floor is 0.15( g = 10 m s−2). $\mu $N |
$50 ms^{-2}$ $1.2 ms^{-2}$ $150 ms^{-2}$ $1.5 ms^{-2}$ |
$1.5 ms^{-2}$ |
For a body to be stationary in cars frame of reference i.e {Non Inertial frame) net force should be equal to zero. Hence frictional force must balance the pseudo force. $\Rightarrow ma =f_s = \mu_s N = \mu_s mg $ $\Rightarrow a = \mu_s g = 0.15\times 10 m/s^2 = 1.5 m/s^2$ |