Two chords AB and CD of a circle intersect at a point P inside the circle. If AB = 11 cm, PC = 3 cm and AP = 5 cm, then CD is equal to?
Answer & explanation
Correct answer: option 1
PA × PB = PC × PD
5 × 6 = 3 × x
x = 10
CD = 13 cm
Two chords AB and CD of a circle intersect at a point P inside the circle. If AB = 11 cm, PC = 3 cm and AP = 5 cm, then CD is equal to?
Correct answer: option 1
PA × PB = PC × PD
5 × 6 = 3 × x
x = 10
CD = 13 cm