Practicing Success
Practicing Success
CUET Preparation Today
The binding energy per nucleon is 1.1 MeV for ${ }_1^2 \mathrm{H}$ and 7.0 MeV for ${ }_2^4 He$. The energy released in the given fusion reaction will be ${ }_1^2 H+{ }_1^2 H \rightarrow{ }_2^4 He$ |
1.1 MeV 11.9 MeV 23.6 MeV 28.0 MeV |
23.6 MeV |
The correct answer is Option (3) → 23.6 MeV |
