The absissa of the point on the curve \(3y=6x-5x^3\), the normal at which passes through origin is
Answer & explanation
Correct answer: option 1
The equation of normal is given by \(y-y_1=(-\frac{1}{\frac{dy}{dx}})(x-x_1)\)
The absissa of the point on the curve \(3y=6x-5x^3\), the normal at which passes through origin is
Correct answer: option 1
The equation of normal is given by \(y-y_1=(-\frac{1}{\frac{dy}{dx}})(x-x_1)\)