A parallel plate capacitor is charged to 60μC. Due to a radioactive source, the plate loss charge at the rate of 1.8 × 10−8 Cs−1 . The magnitude of displacement current is
Answer & explanation
Correct answer: option 1
Displacement current is given by
$I_d=\frac{dq}{dt}= 1.8×10^{-8} \,Cs^{-1}$