A parallel plate capacitor is charged to 60μC. Due to a radioactive source, the plate loss charge at the rate of 1.8 × 10−8 Cs−1 . The magnitude of displacement current is

1.8 × 10−8 Cs−1 3.6 × 10−8 Cs−1 4.1× 10−11 Cs−1 5.7× 10−12 Cs−1

1.8 × 10−8 Cs−1

Displacement current is given by $I_d=\frac{dq}{dt}= 1.8×10^{-8} \,Cs^{-1}$