The circumference of a circular field is 396 m and that of the other circular field is 132 m. Find the area (in m²) of the third circular field whose radius is the sum of the radii of the first two fields. (Take $π =\frac{22}{7}$)

22176

Circumference of 1st circle = 396 cm

2 × π × r1 = 396

2 × \(\frac{22}{7}\) × r1 = 396

r1 = 63 cm

Now,

Circumference of 2nd circle = 132 cm

2 × π × r2 = 132

2 × \(\frac{22}{7}\) × r2 = 132

r2 = 21 cm 

Radius of new circular field = 63 + 21 = 84 cm

Area of new circular field = πr²

= \(\frac{22}{7}\) × 84 ×  84

= 22176