Practicing Success
Three processes compose a thermodynamic cycle shown in the accompany P-V, diagram of an ideal gas : Process 1\(\rightarrow\)2 takes place at constant temperature, during this process 60 J of heat enters the system Process 2\(\rightarrow\)3 takes place at constant volume, during this process 40 J of heat leaves the system Process 3\(\rightarrow\)1 is adiabatic What is the change in internal energy of the system during process 3\(\rightarrow\)1 ? |
- 40 J - 20 J + 20 J + 40 J |
+ 40 J |
1\(\rightarrow\)2 : isothermal; \(\Delta U_{12}\) = 0 2\(\rightarrow\)3 : isochoric; \(\Delta W\) = 0 \(\Rightarrow \Delta Q_{23} \Rightarrow -40 = \Delta U_{23}\) For a cyclic process : \(\Delta U\) = 0 \(\Delta U_{12} + U_{23} + U_{31} = 0\) 0 + (-40) + \(\Delta U_{31}\) = 0 \(\Delta U_{31}\) = + 40 J |