Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Inverse Trigonometric Functions

Question:

The values of $tan^2(sec^{-1}2)+cot^2(cosec^{-1}3),$ is

Options:

5

10

11

15

Correct Answer:

11

Explanation:

$tan^2(sec^{-1}2)+cot^2(cosec^{-1}3)$

$= sec^2 (sec^{-1}2) - 1 + cosec^2 (cosec^{-1}3)-1$

$= \begin{Bmatrix}sec(sec^{-1}2)\end{Bmatrix}^2 -1 +\begin{Bmatrix}cosec(cosec^{-1}3)\end{Bmatrix}^2-1$

$=2^2 - 1 + 3^2 - 1 =11$