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Average of 50 numbers was calculated as 20 when three numbers, 26, 36 and 64 were wrongly read as 31, 46 and 59 respectively. What is the correct average? |
26.2 19.8 20.2 24.4 |
19.8 |
Difference in sum due to wrong entry =( 28 + 36 + 64) - ( 31 + 46 + 59) = -8 Correct average = 20 - \(\frac{8}{50}\) = 19.84 = 19.8 |
