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CUET
-- Mathematics - Section B1
Applications of Derivatives
$3^{500}(mod\, 7)=$
0
1
2
4
The correct answer is Option (3) → 2
Since the cycle repeats every 6 terms,
$500\,mod\,6$
thus,
$500≡2\,mod\,6$
$⇒3^{500}≡2\,mod\,7$
⇒ Remainder = 2