CUET Preparation Today
CUET
-- Applied Mathematics - Section B2
Numbers, Quantification and Numerical Applications
$3^{500}(mod\, 7)=$
0
1
2
4
The correct answer is Option (3) → 2
Since the cycle repeats every 6 terms,
$500\,mod\,6$
thus,
$500≡2\,mod\,6$
$⇒3^{500}≡2\,mod\,7$
⇒ Remainder = 2
