Two point charges qA = 3 µC and qB = -3 µC are located 2 m apart in vacuum. The electric field at midpoint of the line joining the two charges is:

\(5.4 \times 10^4 \mathrm{~N} / \mathrm{C} \) \(1.35 \times 10^4 \mathrm{~N} / \mathrm{C} \) \(2.7 \times 10^4 \mathrm{~N} / \mathrm{C} \) Zero

\(5.4 \times 10^4 \mathrm{~N} / \mathrm{C} \)

Electric field at mid point due to both charges are in the same direction. $\Rightarrow E = 2 \frac{kQ}{r^2} = \frac{2\times 9\times 10^9 \times 3\times 10^{-6}}{1^2} = 5.4 \times 10^4 N/C$