Consider the following hypothesis test

$H_0 : \mu ≥ 16$

$H_1 : \mu < 16 $

A sample of 36 provided a sample mean of 15.4. The population standard deviation is 3. The value of the test statistics 't' is,

-1.2

The correct answer is Option (3) → -1.2

The test statistic is calculated as,

$z=\frac{\bar x-μ_0}{σ/\sqrt{n}}$

$=\frac{15.4-16}{3/\sqrt{36}}=-\frac{0.6}{0.5}$

$=-1.2$