Consider the following hypothesis test
$H_0 : \mu ≥ 16$
$H_1 : \mu < 16 $
A sample of 36 provided a sample mean of 15.4. The population standard deviation is 3. The value of the test statistics 't' is,
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → -1.2
The test statistic is calculated as,
$z=\frac{\bar x-μ_0}{σ/\sqrt{n}}$
$=\frac{15.4-16}{3/\sqrt{36}}=-\frac{0.6}{0.5}$
$=-1.2$