If \(\sqrt { 3}\)sinθ - 1cosθ = 0 , 0° < θ < 90°, then find θ.
Answer & explanation
Correct answer: option 4
\(\sqrt { 3}\)sinθ - 1cosθ = 0
\(\frac{sinθ}{cosθ}\) = \(\frac{1}{√3}\)
tanθ = \(\frac{1}{√3}\)
θ = 30°
If \(\sqrt { 3}\)sinθ - 1cosθ = 0 , 0° < θ < 90°, then find θ.
Correct answer: option 4
\(\sqrt { 3}\)sinθ - 1cosθ = 0
\(\frac{sinθ}{cosθ}\) = \(\frac{1}{√3}\)
tanθ = \(\frac{1}{√3}\)
θ = 30°