Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Probability

Question:

Let X denotes the number of hours a person uses a mobile and the probability distribution of X is as

X

0

1

2

3

4

P(X)

  0.1  

  K  

  2K  

  2K  

  K  

Then the value of K is

Options:

0.15

0.20

0.12

0.16

Correct Answer:

0.15

Explanation:

The correct answer is Option (1) → 0.15

Given the probability distribution:

$X$01234
$P(X)$0.1$K$$2K$$2K$$K$

Sum of all probabilities must equal 1:

$0.1 + K + 2K + 2K + K = 1$

$0.1 + 6K = 1$

$6K = 1 - 0.1 = 0.9$

$K = \frac{0.9}{6} = 0.15$