Practicing Success
The points (0, -1, -1), (-4, 4, 4), (4, 5, 1) and (3, 9, 4) are |
collinear coplanar forming a square none of these |
coplanar |
Equation of the plane passing through the points (0, -1, -1), (-4, 4, 4) and (4, 5, 1) is $\begin{vmatrix}x&(y+1)&(z+1)\\-4&5&5\\4&6&2\end{vmatrix}= 0$ …. (1) The point (3, 9, 4) satisfies the equation (1). Hence (B) is the correct answer. |