Practicing Success
a b c d |
b |
$ E_B - E_A = \frac{hc}{\lambda_2}$ $ E_C - E_B = \frac{hc}{\lambda_1}$ $ E_C - E_A = \frac{hc}{\lambda_3}$ $ E_C - E_A = (E_C - E_B)+(E_B - E_A)$ $\Rightarrow \frac{hc}{\lambda_3} = \frac{hc}{\lambda_1} + \frac{hc}{\lambda_2}$ $\Rightarrow \frac{1}{\lambda_3} = \frac{1}{\lambda_1} + \frac{1}{\lambda_2}$ $\Rightarrow \lambda_3 = \frac{\lambda_1\lambda_2} {\lambda_1+\lambda_2}$ |