If a square has a diagonal of length $6\sqrt{2}$cm, then the area of square is :

48 cm2 72 cm2 16 cm2 36 cm2

36 cm2

Digonal of square having side "a" = $a\sqrt{2}$. ATQ, Digonal = $a\sqrt{2}$ = $6\sqrt{2}$. Therfore, a = 6 cm Area of the square = a2 = 62 = 36 cm2