The number of all possible matrices of order 3 with each entry either 0 or 1 is: |
18 8 256 512 |
512 |
The correct answer is Option (4) → 512 Matrix order: 3 × 3 → 9 entries Each entry can be 0 or 1 → 2 choices per entry Total possible matrices = $2^9 = 512$ |