If a,b,c are all non-zero and a + b + c = 0 find the value of $\frac{a^2}{bc}+\frac{b^2}{ca}+\frac{c^2}{ab}$

3

 a + b + c = 0

Put the values of a = 2 , b = -1 and c = -1

$\frac{a^2}{bc}+\frac{b^2}{ca}+\frac{c^2}{ab}$ = $\frac{2^2}{-1 × -1}+\frac{-1^2}{-1 × 2}+\frac{-1^2}{2 × -1}$

= 4 - \(\frac{1}{2}\) - \(\frac{1}{2}\)

= 4 - 1 = 3