For the function $f(x) =\left\{\begin{matrix}\frac{1-x}{|x-1|}&;x<1\\1&;x=1\\x^2&;x>1\end{matrix}\right.$ which of the following is true |
it is continuous at all points it is continuous at all points except at x = 1 it is differentiable at all points none |
it is continuous at all points |
The correct answer is Option (1) → it is continuous at all points $f(x) =\left\{\begin{matrix}\frac{1-x}{|x-1|}&;x<1\\1&;x=1\\x^2&;x>1\end{matrix}\right.$ we know, $|x-1|=1-x$ for $x<1$ $⇒f(x) =\left\{\begin{matrix}1&;x<1\\1&;x=1\\x^2&;x>1\end{matrix}\right.$ $LHL=\lim\limits_{x→1^-}f(x)=1$ $f(1)=1$ $\lim\limits_{x→1^+}f(x)=(1)^2=1$ $LHL=RHL=f(1)$ f is continuous for every x |