AC is the diameter of the circle. B is a point on the circumference. If angle BAC is 40o, then what is angle BCA?

50o 90o 55o 40o

50o

as AC = Diameter Therefore, \(\angle\)B = \({90}^\circ\) now \(\angle\)CBD = 180 - 130 - 110 = \({40}^\circ\) Therefore, \(\angle\)DBA = \({90}^\circ\) - \(\angle\)CBD = 90 - 40 = 50 Therefore x is \({50}^\circ\).