AC is the diameter of the circle. B is a point on the circumference. If angle BAC is 40o, then what is angle BCA?
Answer & explanation
Correct answer: option 1
as AC = Diameter
Therefore, \(\angle\)B = \({90}^\circ\)
now \(\angle\)CBD = 180 - 130 - 110
= \({40}^\circ\)
Therefore, \(\angle\)DBA = \({90}^\circ\) - \(\angle\)CBD
= 90 - 40 = 50
Therefore x is \({50}^\circ\).