Practicing Success
Practicing Success
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If a + \(\frac{1}{a}\) = -2, then a17 + \(\frac{1}{a^{102}}\) equals to: |
0 2 7 9 |
0 |
a + \(\frac{1}{a}\) = -2 [If a + \(\frac{1}{a}\) = -2, then a = -1 ⇒ a + \(\frac{1}{a}\) = 2 ⇒ a = 1 (always)] So, (-1)17 + \(\frac{1}{(-1)^{102}}\) = -1 + 1 = 0 |
