Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

The electric field intensity at a point is $(20 \hat{i}+15 \hat{j})$ N/C. Considering potential at origin to be zero, the potential at P(2, 2) is

Options:

$-(40 \hat{i}+60 \hat{j})$ V

$-(10 \hat{i}+15 \hat{j})$ V

-100 V

20 V

Correct Answer:

-100 V

Explanation:

$V=-\left[\int\limits_0^x E_x d x+\int\limits_0^y E_y d y\right]=-\left[E_x . x+E_y . y\right]=-100 V$