Practicing Success
The electric field intensity at a point is $(20 \hat{i}+15 \hat{j})$ N/C. Considering potential at origin to be zero, the potential at P(2, 2) is |
$-(40 \hat{i}+60 \hat{j})$ V $-(10 \hat{i}+15 \hat{j})$ V -100 V 20 V |
-100 V |
$V=-\left[\int\limits_0^x E_x d x+\int\limits_0^y E_y d y\right]=-\left[E_x . x+E_y . y\right]=-100 V$ |