The function given by $f(x)=|x-1|+|x-2|+|x-3|$ is :
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → Continuous but not differentiable at x=1, 2 and 3
$f(x)=|x|$ is not differentiable at $x=0$ but continuous every where
$⇒f(x)=|x-1|+|x-2|+|x-3|$ is continuous every where but not differentiable at $x=1,2,3$