Practicing Success
Practicing Success
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The function given by $f(x)=|x-1|+|x-2|+|x-3|$ is : |
Continuous and differentiable for all x $\in $ R. Continuous everywhere but differentiable at x=1, 2 and 3 only Continuous but not differentiable at x=1, 2 and 3 Differentiable but not continuous at x=1, 2 and 3 |
Continuous but not differentiable at x=1, 2 and 3 |
The correct answer is Option (3) → Continuous but not differentiable at x=1, 2 and 3 $f(x)=|x|$ is not differentiable at $x=0$ but continuous every where $⇒f(x)=|x-1|+|x-2|+|x-3|$ is continuous every where but not differentiable at $x=1,2,3$ |
