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If A is a square matrix such that $A^2 = A$ and I is the identity matrix of the same order as A, then $(I+A)^2-3A$ is equal to |
$I$ $2A$ $3I$ $A$ |
$I$ |
The correct answer is Option (1) → $I$ Given$A^2 = A$, $I$ is the identity matrix Compute $(I + A)^2 - 3A$: $(I + A)^2 - 3A = I^2 + IA + AI + A^2 - 3A = I + A + A + A - 3A = I + 3A - 3A = I$ |
