Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Alternating Current

Question:

The peak current flowing through a circuit is 2.5 A at a frequency of 60 Hz. What will be the r.m.s. voltage through the circuit if it consists of 25 \(\Omega \).

Options:

44 V

22 V

66 V

33 V

Correct Answer:

44 V

Explanation:

Irms = 2.5 A/1.414 = 1.77 A

Vrms = 1.77 A x 25 \(\Omega \) = 44 V