Practicing Success
The binding energies per nucleon for a deuteron and an $\alpha$-particle are $x_1$ and $x_2$ respectively. What will be the energy Q released in the reaction ${ }_1 H^2+{ }_1 H^2 \rightarrow_2 H e^4+Q$ |
$4\left(x_1+x_2\right)$ $4\left(x_2-x_1\right)$ $2\left(x_1+x_2\right)$ $2\left(x_2-x_1\right)$ |
$4\left(x_2-x_1\right)$ |
Q = 4 $\left(x_2-x_1\right)$ |