The binding energies per nucleon for a deuteron and an $\alpha$-particle are $x_1$ and $x_2$ respectively. What will be the energy Q released in the reaction ${ }_1 H^2+{ }_1 H^2 \rightarrow_2 H e^4+Q$
Answer & explanation
Correct answer: option 2
Q = 4 $\left(x_2-x_1\right)$