Practicing Success
Practicing Success
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If 9 secθ = 41 . Then find the value of 5cotθ . |
5 \(\frac{9}{8}\) \(\frac{1}{8}\) \(\frac{9}{40}\) |
\(\frac{9}{8}\) |
9 secθ = 41 secθ = \(\frac{41}{9}\) (where 41 → H and 9 → B) P = \(\sqrt {(41)^2 - (9)^2}\) P = \(\sqrt {1600}\) = 40 5cotθ = \(\frac{B}{P}\) = 5 × \(\frac{9}{40}\) = \(\frac{9}{8}\) |
