At which point does the line \(3x-2y=12\) cut the x-axis?
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → \((4,\,0)\)
Every point of the x-axis has y-coordinate 0, so the line meets the x-axis where \(y=0\).
Put \(y=0\) in \(3x-2y=12\): \(3x=12\)
\(x=4\)
The line cuts the x-axis at \((4,\,0)\)
