If h is the Planck's constant, then the momentum of the photon having frequency $v$ is represented by |
$hcv$ $hv/c$ $hc/v$ $h/cv$ |
$hv/c$ |
The correct answer is Option (2) → $hv/c$ Energy of a photon: $E = h \nu$ Relativistic relation between energy and momentum for a photon: $E = pc$ So, momentum: $p = \frac{E}{c} = \frac{h \nu}{c}$ Final Answer: $p = \frac{h \nu}{c}$ |