Match List-I with List-II

Choose the correct answer from the options given below:

(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

The correct answer is Option (1) → (A)-(II), (B)-(IV), (C)-(I), (D)-(III)

(A) Einstein's photoelectric Equation → (II) $K_{max} = \frac{hc}{\lambda} - \phi$

This is the fundamental relation for photoelectric emission, showing how the energy of an incident photon is used to overcome the work function ($\phi$) and the rest appears as kinetic energy ($K_{max}$) of the emitted electron.

(B) de-Broglie wavelength → (IV) $\frac{h}{p}$

According to de Broglie, any moving particle has a wavelength associated with it, inversely proportional to its momentum ($p$). This shows the wave nature of matter.

(C) Stopping potential → (I) $\frac{K_{max}}{e}$

The stopping potential is the potential needed to stop the fastest photoelectrons. It is related to their maximum kinetic energy by this formula.

(D) Threshold wavelength → (III) $\frac{hc}{\phi}$

The threshold wavelength is the longest wavelength (least energy) of light that can just cause photoemission. It's derived by setting $K_{max} = 0$ in Einstein’s equation.