In Binomial distribution, if $E(X)=40 $ and $V(X)=8, $ then value of $P(X=1), $ is : |
$\frac{8}{5^{48}}$ $\frac{2}{5^{49}}$ $\frac{3}{5^{49}}$ $\frac{7}{5^{49}}$ |
$\frac{8}{5^{48}}$ |
The correct answer is Option (1) → $\frac{8}{5^{48}}$ In a Binomial Distribution, Mean = $E(X)=np=40$ [Given] ...(1) Variance = $V(X)=np(1-p)=8$ [Given] ...(2) Substituting $np=40$ in equation (2) $40(1-p)=8$ $1-p=\frac{1}{5}$ $p=\frac{4}{5}$ $⇒n=40×\frac{5}{4}=50$ $P(X+1)={^{50}C}_1(\frac{4}{5})(\frac{1}{5})^{49}$ $=\frac{8}{5^{48}}$ |