Five equal resistors when connected in series dissipated 5 W power. If they are connected in parallel, the power dissipated will be:
Answer & explanation
Correct answer: option 4
In series, total resistance of 5 resistors = 5R
or $=\frac{\mathrm{V}^2}{\mathrm{R}}$ = 25
In parallel, total power $=5\left(\frac{\mathrm{V}^2}{\mathrm{R}}\right)=5 \times 25$ = 125 W