Five equal resistors when connected in series dissipated 5 W power. If they are connected in parallel, the power dissipated will be:

25 W 50 W 100 W 125 W

125 W

In series, total resistance of 5 resistors = 5R or $=\frac{\mathrm{V}^2}{\mathrm{R}}$ = 25 In parallel, total power $=5\left(\frac{\mathrm{V}^2}{\mathrm{R}}\right)=5 \times 25$ = 125 W