A man of 50 kg mass is standing in a gravity free space at a height of 10 m above the floor. He throws a stone of 0.5 kg mass downwards with a speed 2 m/s. When the stone reaches the floor, the distance of the man above the floor will be :

20 m 9.9 m 10.1 m 10 m

10.1 m

\(m_1x_1 = m_2x_2\) \(m_1 = 0.5 kg ; x_1 = 10 m ; m_2 = 50 kg \) \(x_1 = 0.1 m\) Total height = 10 + 0.1 = 10.1 m